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CH7003 – Practice Problem Set 1

1. Q1. The following parallel reactions are known to occur (C_A is the concentration of A):

A  R r₁ 10C_A^0.5 Mole/ Lmin

A  S r₂  5C_A Mole/ Lmin

A T r₃  C_A² Mole/ Lmin

Q2.The feed concentration is C_A0=10 mole/L. The volumetric flow rate is 1000L/min. T is the desired product.

• Find the optimum selectivity and the conversion at that point. What is the preferred reactor (PF or CSTR)?
• Find the optimum yield and the conversion at that yield. (Please use a graph paper)
• Express r in terms of C_A and describe how you can graphically determine the volume of reactor needed.

2. Q3. CSTR and PFTR reactors are used in series for the reaction A 4B, r = kC_A². The feed consists of 90 mol% A and 10mol% inert gas. A, B, and the inert gas can be regarded as ideal gases. v₀ = 5 liter/min, k = 1 liter/mole min, and C_A0 = 2 moles/liter. If the conversion after the first reactor is set at 50% and after the second reactor is set at 80%, how should you arrange the reactors to minimize the reactors’ total volume, and what should be the sizes of these two reactors?

3. A 100‐Litre CSTR is used for a reaction that follows a 2nd‐order rate law:

‐r_a = kC_A0²(1‐X)²

where X is the conversion and C_A0 is the inlet concentration of the limiting reactant. A conversion of 75% is achieved in the CSTR. A PFR of the same volume is added in series to the CSTR to increase the conversion. Should it be added before or after the CSTR? What is the final conversion?

4. Three reactions occur in an isothermal batch reactor:

A —> B r₁=k₁C_A k₁=0.40 h^‐1

A —> C + D r₂=k₂C_A k₂=0.15 h^‐1

2A —> E r₃=k₃C_A k₃=0.35 h^‐1

Given the following initial concentrations, what is reaction time needed for 90% conversion?

C_A0= 10 mol/L C_B0= 0 mol/L Cc₀= 0.8 mol/L C_D0= 0.8 mol/L C_E0= 0.5 mol/L

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