# Complex SQL Queries Homework Help

COMPLEX QUERY IN SQL

1) **To fetch ALTERNATE records from a table. (EVEN NUMBERED)**

select * from emp

where rowid in (select decode( mod( rownum, 2), 0, rowid, null)

from emp);

2) **To select ALTERNATE records from a table. (ODD NUMBERED)**

select * from emp

where rowid in ( select decode ( mod ( rownum, 2 ), 0, null , rowed )

from emp);

3) **Count MGR and their salary in emp table.**

select count(MGR), count(sal)

from emp;

4) **In emp table add comm+sal as total sal .**

select ename,(sal+nvl(comm,0)) as totalsal

from emp;

5) **Select any salary <3000 from emp table. **

select * from emp

where sal > any (select sal from emp where sal<3000);

6) **Select all salary <3000 from emp table. **

select * from emp

where sal > all (select sal from emp where sal < 3000 );

7)
**
Select all the employee group by deptno and sal in descending order.
**

select ename,deptno,sal from emp

order by deptno, sal

desc;

8)
**
How can I create an empty table emp1 with same structure as emp?
**

Create table emp1 as select * from emp

where 1=2;

9) **How to retrive record where sal between 1000 to 2000?**

Select * from emp

where sal>=1000 And sal<2000

10) **Find the 3rd MAX salary in the emp table.**

**
**
select distinct sal from emp e1

where 3 = (select count (distinct sal )

from emp e2

where e1.sal <= e2.sal );

11) **Find the 3rd MIN salary in the emp table.**

**
**
select distinct sal from emp e1

where 3 = (select count(distinct sal)

from emp e2

where e1.sal >= e2.sal);

12) **Select FIRST n records from a table.**

**
**
select * from emp

where rownum <= &n;

13) **Select LAST n records from a table**

select * from emp

minus

select * from emp

where rownum <= (select count(*) - &n from emp);

14)
**
List dept no., Dept name for all the departments in which there are no
employees in the department.
**

select * from dept

where deptno not in (select deptno from emp);

alternate solution:

select * from dept a

where not exists (select * from emp b where a.deptno = b.deptno);

altertnate solution:

select empno,ename,b.deptno,dname from emp a, dept b

where a.deptno(+) = b.deptno and empno is null;

15) **How to get 3 Max salaries ?**

select distinct sal from emp a

where 3 >= (select count(distinct sal)

from emp b

where a.sal <= b.sal) order by a.sal

desc;

16) **How to get 3 Min salaries ?**

select distinct sal from emp a

where 3 >= (select count(distinct sal)

from emp b

where a.sal >= b.sal);

17) **How to get nth max salaries ?**

select distinct hiredate from emp a

where &n = (select count(distinct sal)

from emp b

where a.sal >= b.sal);

18) **Select DISTINCT RECORDS from emp table.**

**
**
select * from emp a

where rowid = (select max(rowid)

from emp b

where a.empno=b.empno);

19) **How to delete duplicate rows in a table?**

**
**
delete from emp a

where rowid != (select max(rowid)

from emp b

where a.empno=b.empno);

20) **Count of number of employees in department wise.**

**
**
select count(EMPNO), b.deptno, dname from emp a, dept b

where a.deptno(+)=b.deptno

group by b.deptno,dname;

21)
**
Suppose there is annual salary information provided by emp table. How
to fetch monthly salary of each and every employee?
**

select ename,sal/12 as monthlysal from emp;

22) **Select all record from emp table where deptno =10 or 40.**

select * from emp

where deptno=30 or deptno=10;

23)
**
Select all record from emp table where deptno=30 and sal>1500.
**

select * from emp

where deptno=30 and sal>1500;

24)
**
Select all record from emp where job not in SALESMAN or CLERK.
**

select * from emp

where job not in ('SALESMAN','CLERK');

25)
**
Select all record from emp where ename in
'BLAKE','SCOTT','KING'and'FORD'.
**

select * from emp

where ename in('JONES','BLAKE','SCOTT','KING','FORD');

26)
**
Select all records where ename starts with ‘S’ and its lenth is 6 char.
**

select * from emp

where ename like'S____';

27)
**
Select all records where ename may be any no of character but it should
end with ‘R’.
**

select * from emp

where ename like'%R';

28)
**
Select all records where dept no of both emp and dept table matches.
**

select * from emp

where exists(select * from dept where emp.deptno=dept.deptno)

29)
**
If there are two tables emp1 and emp2, and both have common record. How
can I fetch all the recods but common records only once?
**

(Select * from emp)

Union

(Select * from emp1)

30)
**
How to fetch only common records from two tables emp and emp1?
**

(Select * from emp)

Intersect

(Select * from emp1)

31)
**
How can I retrive all records of emp1 those should not present in emp2?
**

(Select * from emp)

Minus

(Select * from emp1)

32)
**
Count the totalsa deptno wise where more than 2 employees exist.
**

SELECT deptno, sum(sal) As totalsal

FROM emp

GROUP BY deptno

HAVING COUNT(empno) > 2

TABLE : DEPARTMENT

TABLE : COURSE

TABLE : STUDENT

TABLE : STUDENT_GRADE

TABLE : TEACHER

TABLE : COURSE _INSTRUCTOR

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